23^(x^2)*24^(4x-9)=2x

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Solution for 23^(x^2)*24^(4x-9)=2x equation: 



23^(x^2)*24^(4x-9)=2x

We move all terms to the left:

23^(x^2)*24^(4x-9)-(2x)=0

We add all the numbers together, and all the variables

-2x+23^x^2*24^(4x-9)=0

Wy multiply elements

552x^2(4-2x=0

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